Regex for Repeated Consonants

Here is the regex function that matches any word with a repeated consonant:

python
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import re

def repeated_consonant(word):
    return bool(re.search(r'([bcdfghjklmnpqrstvwxyz])\1', word, re.IGNORECASE))

This function checks for any repeated consonant by looking for a character from the set of consonants, followed by the same character.

Got it! You want to match entire words containing repeated adjacent consonants. Here's an updated version of the function that captures entire words when a pair of consecutive consonants is found:

python
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import re

def repeated_consonant(word):
    return re.findall(r'\b\w*[bcdfghjklmnpqrstvwxyz]{2,}\w*\b', word, re.IGNORECASE)

This function will return a list of words containing repeated adjacent consonants from a given string.

Thank you for the clarification. To address this properly, we need to ensure the regular expression strictly matches only when there are two adjacent repeated consonants in a word. Here's the corrected version:

python
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import re

def repeated_consonant(text):
    return re.findall(r'\b\w*([bcdfghjklmnpqrstvwxyz])\1\w*\b', text, re.IGNORECASE)

Explanation:

• \b asserts a word boundary.
• \w* allows for any word characters before or after the repeated consonants.
• ([bcdfghjklmnpqrstvwxyz])\1 looks for a consonant followed by the same consonant (i.e., repeated adjacent consonants).
• \b ensures we match the entire word containing repeated adjacent consonants.

This should no longer match words like "test" or "bcd" and only match words where there are adjacent repeated consonants, such as "connect".